8.EE.B.5 8th Grade Expressions & Equations

Proportional Relationships

Graph proportional relationships, interpret the unit rate as the slope, and compare two proportional relationships represented in different ways.

How to explain it

The anchor students hold onto: To find k: pick any point (x, y) on the line — not the origin — and compute k = y ÷ x. To compare two relationships, the larger k means the steeper graph and the greater rate.

Students extend proportional graphs to slope-intercept form y = mx + b in Slope-Intercept Form, then graph and compare equations of all forms in Graphing Linear Equations.

Worked examples

Example 1 Find k from an equation
Find k for y = 6x.
Step 1y = kx form: the coefficient of x is k.
Step 2Read off: k = 6.
Step 3Unit rate: 6 units of y per 1 unit of x.
Answerk = 6; equation is y = 6x.
Example 2 Compare two relationships
Compare y = 4x and y = x.
Step 1Read each k: first equation k = 4; second k = 1.
Step 2Compare: 4 > 1.
Step 3The larger k means a steeper line and greater rate.
Answery = 4x has the greater unit rate (k = 4 vs k = 1).

Common mistakes

What students write Dividing x by y instead of y by x — computing k = x / y returns the reciprocal, not k.
The fix k = y / x: the output variable (y) is always the numerator. Divide y by x, not x by y.
Try this A student claims y = 3x + 2 is a proportional relationship because the graph is a straight line and has x in the equation. Identify the student's error. Explain how to check whether a relationship is proportional.
What students write Calling y = 3x + 2 proportional because it has y = kx structure with a coefficient visible.
The fix Substitute x = 0: y = 2, not 0. The graph misses the origin — proportional requires y = 0 when x = 0.

Teacher tip

Head off the two predictable errors before they happen. First: k = y / x: the output variable (y) is always the numerator. Divide y by x, not x by y. Second: Substitute x = 0: y = 2, not 0. The graph misses the origin — proportional requires y = 0 when x = 0.